A particle carrying charge + q is located at the center of a square with sides o

Question

A particle carrying charge +q is located at the center of a square with sides of length l .

If you leave the corner particles in the arrangement determined in part A, but move the center particle to the midpoint of the top side of the square, what is the magnitude of the vector sum of the forces exerted on this particle?

F^E = (7.28kq^2) l l^2

a) If you leave the corner particles in the arrangement determined in part A but move the center particle to the midpoint of the top side of the square, what is the direction angle of the vector sum of the forces exerted on this particle measured counterclockwise from the positive x direction?

= __________

Explanation / Answer

When we move the center particle to the midpoint of the top side of the square, The Net Force from the bottom charges will be to the Left , and the Net force due to top charge will be to the Right !!
As the Top charges will exert greater force, Therefore Net Force will be towards +ve x axis !!

So the Angle measured counterclockwise from the positive x direction , = 0o

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