A particle (charge = 40 C) moves directly toward asecond particle (charge = 80 C

Question

A particle (charge = 40 C) moves directly toward asecond particle (charge = 80 C) which is held on a fixedposition. At an instant when the distance between the two particlesis 2.0 m, the kinetic energy of the moving particle is 16 J.Determine the distance separating the two particles when the movingparticle is momentarily stopped. please show how. A particle (charge = 40 C) moves directly toward asecond particle (charge = 80 C) which is held on a fixedposition. At an instant when the distance between the two particlesis 2.0 m, the kinetic energy of the moving particle is 16 J.Determine the distance separating the two particles when the movingparticle is momentarily stopped. please show how.

Explanation / Answer

the moving particle is momentarily stopped. (it caused by the repulsive force between 2charges) conservation of energy 16+k*40*80/2=k*40*80/x => x{min}=0.947m

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