A particle carrying a charge of 7.0 ? C is located at the origin of a rectangula

Question

A particle carrying a charge of 7.0?C is located at the origin of a rectangular coordinate system, and a particle carrying a charge of 2.0?C is located at(0, 5.0 m).

Part A

What are the x and y components of the magnitude of the electric field at the position (5.0 m, 0)?

Enter your answers numerically separated by a comma.

Ex, Ey= N/C

Part B

What are the x and y components of the magnitude of the electric field at the position (-5.0 m, 0)?

Enter your answers numerically separated by a comma.

Ex, Ey= N/C

Part C

What are the x and y components of the magnitude of the electric field at the position (0, -5.0 m)?

Enter your answers numerically separated by a comma.

Ex, Ey=     N/C

Ex, Ey= N/C

Part B

What are the x and y components of the magnitude of the electric field at the position (-5.0 m, 0)?

Enter your answers numerically separated by a comma.

Ex, Ey= N/C

Part C

What are the x and y components of the magnitude of the electric field at the position (0, -5.0 m)?

Enter your answers numerically separated by a comma.

Ex, Ey=     N/C

  

Explanation / Answer

A particle carrying a charge of 7.0?C is located at the origin of a rectangular coordinate system.

q1 = 7 * 10-6 C               at origin

A particle carrying a charge of 2.0?C is located at(0, 5.0 m).

q2 = 2 * 10-6 C               at   (0, 5.0 m)

k = 8.99 * 109 N.m2 / C2 is the Coulomb's force constant.

Part A

The x and y components of the magnitude of the electric field at the position (5.0 m, 0):

X component:

Ex = k q1 cos 0 / (5)2 + k q2 cos 315 / 2 * (5)2

Ex = 8.99 * 109 * 7 * 10-6 * 1 / 25 + 8.99 * 109 * 2 * 10-6 * 0.707 / 50

Ex = 2.77 * 103 N/C

Y component:

Ey = k q1 sin 0 / (5)2 + k q2 sin 315 / 2 * (5)2

Ey = 8.99 * 109 * 7 * 10-6 * 0 / 25 + 8.99 * 109 * 2 * 10-6 * -0.707 / 50

Ey = -0.25 * 103 N/C

Part B

The x and y components of the magnitude of the electric field at the position (-5.0 m, 0):

X component:

Ex = k q1 cos 180 / (5)2 + k q2 cos 225 / 2 * (5)2

Ex = 8.99 * 109 * 7 * 10-6 * -1 / 25 + 8.99 * 109 * 2 * 10-6 * -0.707 / 50

Ex = -2.77 * 103 N/C

Y component:

Ey = k q1 sin 180 / (5)2 + k q2 sin 225 / 2 * (5)2

Ey = 8.99 * 109 * 7 * 10-6 * 0 / 25 + 8.99 * 109 * 2 * 10-6 * -0.707 / 50

Ey = -0.25 * 103 N/C

Part C

The x and y components of the magnitude of the electric field at the position (0, -5.0 m):

X component:

Ex = k q1 cos 270 / (5)2 + k q2 cos 270 / (10)2

Ex = 8.99 * 109 * 7 * 10-6 * 0 / 25 + 8.99 * 109 * 2 * 10-6 * 0 / 100

Ex = 0 N/C

Y component:

Ey = k q1 sin 270 / (5)2 + k q2 sin 270 / (10)2

Ey = 8.99 * 109 * 7 * 10-6 * -1 / 25 + 8.99 * 109 * 2 * 10-6 * -1 / 100

Ey = -2.697 * 103 N/C

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