1) A planet has twice the mass of the earth but the same radius. What is the acc

Question

1) A planet has twice the mass of the earth but the same radius. What is the acceleration of gravity on the surface of this planet? the same as on earth half as much as on earth one-forth as much as on earth twice as much as on earth O four times as much as on earth. 2) A planet has twice the radius of the earth but the same mass. What is the acceleration of gravity on the surface of this planet? the same as on earth half as much as on earth one-forth as much as on earth twice as much as on earth four times as much as on earth A satellite orbits the earth at a distance equal to twice the earth's radius above the surface of the earth (the total distance from the center of the earth is three times the radius of the earth). 3) The satellite has a mass of 60 kg. What is the force of attraction between the earth and the satellite? 588 N O 318 N 65.3 N 21.0 N 7.26 N 4) What is the centripetal acceleration of the satellite? 88.2 m/s 29.4 m/s2 9.80 m/s 3.27 m/s 1.09 m/s 50 With what speed must the satellite move to follow a circular orbit? 4565 m/s. O 1987 m/s 567 m/s 222 m/s, O 18 m/s

Explanation / Answer

1. Twice that of earth

We know acceleration due to gravity g=(GM)/R^2

The formula will become g=( G*2M)/R^2

g=2(GM)/R^2

2. One fourth as on earth

By the above formula g=(GM)/(2R)^2

g=(GM)/4R

3. 65.3 N

Formula for calculating force between tow objects

F= G(M1*M2)/r^2

G- gravity 6.7*10^-11

M1- Mass of earth (5.98*10^24)

M2- Mass of satellite 60 kg

r- distance between centre of two objects (3 times earth radius)= 3(6.4*10^6)

4.

Centripetal accelacceleration ac=v^2/r

Putting thevalue of v from answer 5 and r from above eq.

1.09 m/s^2

5. Velocity

V= (GMe/r)

Using the above values answer is 4565 m/s

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