A rectangular loop of wire, with dimensions shown in Figure 22-8, carries a curr

Question

A rectangular loop of wire, with dimensions shown in Figure 22-8, carries a current of 2 A and is placed m a magnetic field of 0.8 T The wire rotates in the magnetic field and at one point it is perpendicular to the magnetic field What is the magnitude of the torque acting on the wire? 0 Nm 3 Nm 2Nm 4 Nm 1Nm A circular loop of wire of radius 0.50 m is m a uniform magnetic field of 0.30 T. The current in the loop & 2.0 A What is the magnetic torque when the plane of the loop is perpendicular to the magnetic field? zero 0.58 m N 0.41 m N 0.47 m N 0.52 m N

Explanation / Answer

Torque = MB sin theta
or Torue = BiA sin theta

Here theta =90 degrees
T= BiA
T= Bi (l*b)
T= 0.96 Nm
0r T= 1 Nm

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