A rectangular loop of wire of length 6a and width 2a is located in the x-y plane

Question

A rectangular loop of wire of length 6a and width 2a is located in the x-y plane a distance a away from the x- and y- axes as shown in a region where the magnetic field is in the +y direction with a magnitude that changes in the y-direction as B(y) = 5/y T.The wire carries a current I = 3 A in a clockwise direction and is fixed to a beam through its center that will allow it to rotate. If a = 1.2 m, what is the magnitude of the net torque exerted on the loop by the magnetic field. (Answer in units of Nm).

Explanation / Answer

Tau(torque) = u x B = I * A x B = I * A * B Sin theta where u = I*A (current * area) u x B = u*B*Sin(theta) theta for two sides is 0 degree and 90 degree respectively so add their torque up. Sin 0 is 0 so one side gives 0 torque. Remaining is: Tau = (3A) x [6 x 2 x a(square)] meter square x 5/y x sin90 (:. y is distance from y axis i.e a) put values and find answer

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.