Use the References to access important values if needed for this question. The n

Question

Use the References to access important values if needed for this question. The normal freezing point of water (H2O) is 0.000 °C and its Kp, value is 1.86 °C/m. In a laboratory experiment, students synthesized a new compound and found that when 10.30 grams of the compound were dissolved in 248.0 grams of water, the solution began to freeze at -1.345 'C. The compound was also found to be nonvolatile and a nonelectrolyte. What is the molecular weight they determined for this compound? g/mol Submit Answer

Explanation / Answer

The depressin in freezing point = 1.348 C

mass of solute = 10.80g

mass of water solvent = 248.0g

Kf of water = 1.86 K Kg/mol

Thus molality of solution = [10.80/molar mass]mol/0.248Kg

We know from colligativ eproperties

depression in freezing point = Kf x molality

1.348K = 1.86K.Kg/mol x [10.80/molar mass] mol /0.248Kg

Thus

molar mass of solute = 60.089 g/mol

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