Use the References to access important values if needed for this question. The n

Question

Use the References to access important values if needed for this question. The normal freezing point of water (H2O) is 0.000 °C and its Kp value is 186 °C/m. In a laboratory experiment, students synthesized a new compound and found that when 10.80 grams of the compound were dissolved in 248.0 grams of water, the solution began to freeze at -1.343 'C. The compound was also found to be nonvolatile and a nonelectrolyte. What is the molecular weight they determined for this compound? g/mol Submit Answer

Explanation / Answer

T = i*kf*m

T = change in Temperature ,

i= vont Hoff factor ( for non electrolyte it is unity)

Kf = 1.86 m/°C

m = molality (moles of solute / kg of solvent)

Moles = mass (g) /molar mass (g/mol)

1.348 °C = 1 * 1.86 m/°C * (10.80 g / molar mass g/mol) / 0.248 kg

Molar mass(g/mol) = 1 * 1.86 * 10.80 / (1.348 * 0.248) => 60.09 g/mol

Answer = 60.09 g/mol

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