Use the References to access important values if needed for this question The he
ID: 711657 • Letter: U
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Use the References to access important values if needed for this question The heat of fusion of heptane (CH16) at its normal melting point of -91°C is 14.0 kJ/mol, while its heat of vaporization at its normal boiling point of 98°C is 31.9 kJ/mol. (a) Use these data to calculate the heat of sublimation for CH16 Is your answer precise or is it approximate?' B kJ/mol (b) At 298 K, the standard heat of formation of C,H1-224.2 kJ/mol while the standard heat of formation of C7H16(g) is-187.6 mol. Use this to calculate the heat of vaporization of heptane. Is your result for part (b) larger or smaller than the value given in the statement of the problem? kJ/mol Submit AnswerExplanation / Answer
a) DHsub = DHfus + DHvap
= 14.0+31.9
= 45.9 kj/mol
it is precise value.
b) C7H16(l) <----> C7H16(g)
DHrxn = (-187.6)-(-224.2)= 36.6 kj/mol
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