Four capacitors are connected as shown in the figure below (Let C 3 10.0 HF.) 3.

Question

Four capacitors are connected as shown in the figure below (Let C 3 10.0 HF.) 3.00 MF 20.0 F 6.00 uF (a) Find the equivalent capacitance between points a and b 5.8 HF (b) Calculate the charge on each capacitor, taking AVab 18.0 V. 20.0 HF capacitor 104.4 HCE 6.00 HF capacitor 76.68 HCE 27.72 x 3.00 HF capacitor You are correct that the charge on this capacitor plus the charge on the 6 HF capacitor must be equal to the charge on the 20 HF capacitor. HC 27.4 Capacitor C You are correct that the charge on this capacitor will be the same as the charge on the 3 HF capacitor. HC

Explanation / Answer

equivalent capacitance

C and 3 uF are in series

10*3/(10+3)=2.31 uF

2.31 and 6 uF are in parallel

2.31+6=8.31 uF

8.31 and 20 uF are in series

Ceq=8.31*20/(8.31+20)

Ceq=5.8 uF

b)

Total charge

Q=Ceq*V=18*5.8=104.4 uF

so charge on each capacitor us

Q(20)=Q=104.4 uF

Q(6)=Q*(6/6+2.3) =104.4 *(6/8.3)=75.5 uC

Q(3)=Q*(2.3/2.3+6) =104.4*(2.3/8.3) =28.9 uC

Q(C)=28.9 uC

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.