Four acrobats of mass 63.0 kg, 68.0 kg, 62.0 kg, and 55.0 kg form a human tower,

Question

Four acrobats of mass 63.0 kg, 68.0 kg, 62.0 kg, and 55.0 kg form a human tower, with each acrobat standing on the shoulders of another acrobat. The 63.0-kg acrobat is at the bottom of the tower.
(a) What is the normal force acting on the 63.0-kg acrobat?
(answer in Newtons)

(b) If the area of each of the 63.0-kg acrobat's shoes is 435 cm2, what average pressure (not including atmospheric pressure) does the column of acrobats exert on the floor?
(answer in Pascals)

(c) Will the pressure be the same if a different acrobat is on the bottom?

Explanation / Answer

a) normal force on 63 kg acrobat is = (63+68+62+55)*9.81 = 2432.88N b) pressure = force / area = 2432.88/ (2*0.435) = 2796.41 c) pressure will be same irrespective of the acrobat on the bottom.. (if area is same)

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