Four acrobats of mass 90.0 kg, 68.0 kg, 62.0 kg, and 55.0 kg form a human tower,

Question

Four acrobats of mass 90.0 kg, 68.0 kg, 62.0 kg, and 55.0 kg form a human tower, with each acrobat standing on the shoulders of another acrobat. The 90.0-kg acrobat is at the bottom of the tower.

(a) What is the normal force acting on the 90.0-kg acrobat?
N

(b) If the area of each of the 90.0-kg acrobat's shoes is 480 cm2, what average pressure (not including atmospheric pressure) does the column of acrobats exert on the floor?
Pa

(c) Will the pressure be the same if a different acrobat is on the bottom?

Explanation / Answer

a)
The four stand on eachother.
Total mass of top of 90 kg acrobat = 68 + 62 + 55 = 175 kg
weight = 1813 N
total weight of four people = 275 * 9.8 = 2675 N

So, normal contace force on top shoulders of 90 kg acrobat = 1813 N
normal force on feet of acrobat 90kg from ground = 2675 N

Answer b)

Area of ground = 480 sq.cm = 0.048 m2
Pressure by column on ground = F/A = 2675/0.048 = 55729.166 Pa

Answer c)

Pressure on ground will remain same irrespective to arrangement of acrobats vertically provided the same four stand.
If a new acrobat of mass not equal to 90 kg, replaces the 90kg acrobat while other three being the same, THEN PRESSURE SHALL CHANGE.

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