A ladder of length 20.0m is carried by a fire truck. The ladder has a weight of

Question

A ladder of length 20.0m is carried by a fire truck. The ladder has a weight of 3000N and its center of gravity is at its center. The ladder is pivoted at one end (A) about a pin (Figure 1) ; you can ignore the friction torque at the pin. The ladder is raised into position by a force applied by a hydraulic piston at C. Point C is a distance 8.0mfrom A, and the force F?  exerted by the piston makes an angle of ? = 40? with the ladder.

What magnitude must F?  have to just lift the ladder off the support bracket at B?

Explanation / Answer

F*sin(40)*8 - 3000*10 = 0

F*sin(40) = 3000*10 / 8

F = 5833.96 Newtons

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