A laboratory electromagnet produces a magnetic field of magnitude 1.60 T. A prot
ID: 1545448 • Letter: A
Question
A laboratory electromagnet produces a magnetic field of magnitude 1.60 T. A proton moves through this field with a speed of 6.60 times 10^6 m/s. Find the magnitude of the maximum magnetic force that could be exerted on the proton. N What is the magnitude of the maximum acceleration of the proton? m/s^2 Would the field exert the same magnetic force on an electron moving through the field with the same speed? Yes No Explain. This answer has not been graded yet. Would the electron experience the same acceleration? Yes No Explain.Explanation / Answer
B = 1.6 T , v = 6.6*10^6 m/s
charge of proton q = 1.6*10^-19 C
(a) F = qvB
F = 1.6*10^-19*6.6*10^6*1.6
F = 1.7*10^-12 N
(b) From Newton second law
F = ma
mass of proton m= 1.67*10^-27 kg
1.7*10^-12 = 1.67*10^-27*a
a = 1.02*10^15 m/s^2
(c) Yes
charge of electron is equal to charge of proton, so they experience same force
(d) No
mass of electron is different from mass of proton
mass of electron m = 9.1*10^-31 kg
F = ma
1.7*10^-12 = 9.1*10^-31*a
a = 1.87*10^18 m/s^2
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