A ball of mass 4.9 g with a speed of 22.5 m/s strikes a wall at an angle 29.0 o

Question

A ball of mass 4.9 g with a speed of 22.5 m/s strikes a wall at an angle 29.0o and then rebounds with the same speed and angle. It is in contact with the wall for 45.0 ms. What is the magnitude of the impulse associated with the collision force? What is the average force exerted by the ball on the wall? A ball of mass 4.9 g with a speed of 22.5 m/s strikes a wall at an angle 29.0o and then rebounds with the same speed and angle. It is in contact with the wall for 45.0 ms. What is the magnitude of the impulse associated with the collision force? What is the average force exerted by the ball on the wall?

Explanation / Answer

Let i be the direction perpendicular to the wall and j be parallel to the wall.

Now there is no change in momentum in the j direction

But in the i directions we have J (impulse) = ?px = m*(vfx - vix)
= 0.0049kg*(22.50m/s*sin(29)- (-22.50m/s*sin(29)) = 0.1069N-s i + 0 j

Now F = J/t = 0.1069N-s i /0.045s = 2.375N i

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