A ball of mass 0.140 kg is dropped from rest from a height of1.25 m. It rebounds

Question

A ball of mass 0.140 kg is dropped from rest from a height of1.25 m. It rebounds from the floor to reach a height of0.880 m. What impulse was given to theball by the floor?
______ kg(m)/s A ball of mass 0.140 kg is dropped from rest from a height of1.25 m. It rebounds from the floor to reach a height of0.880 m. What impulse was given to theball by the floor?
______ kg(m)/s A ball of mass 0.140 kg is dropped from rest from a height of1.25 m. It rebounds from the floor to reach a height of0.880 m. What impulse was given to theball by the floor?
______ kg(m)/s

Explanation / Answer

Impulse is equal to change is momentum. I=P so we can find velocities to calculate change inmomentum. V1=2gh1=2*9.8*1.25=24.5 V1=4.949 m/s same process can be used to find V2 V2=2gh2=2*9.8*0.88 V2=4.153 m/s P=m(V1+V2) =0.140(4.153+4.949) P=I=1.274 V2=2gh2=2*9.8*0.88 V2=4.153 m/s P=m(V1+V2) =0.140(4.153+4.949) P=I=1.274

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