QUESTION 1 How many possible states can be represented by a 5-bit state register

Question

QUESTION 1

How many possible states can be represented by a 5-bit state register?

QUESTION 2

When a clock signal changes from 1 to 0, this is referred to as the...

Period

Falling edge

Rising edge

Frequency

QUESTION 3

What is the minimum number of bits required in order for a state register to represent an FSM with 24 states?

0.5 points   

QUESTION 4

What is the clock period for a clock with a frequency of 16 MHz?

Note: This answer will be autograded. Please include units with a single space between the number and the units.

QUESTION 5

What is the frequency of a clock with a period of 50 ms?

Note: This answer will be autograded. Please include units with a single space between the number and the units.

QUESTION 6

How many possible states can be represented by a 10-bit state register?

QUESTION 7

What is the clock period for a clock with a frequency of 3.2 GHz?

Note: This answer will be autograded. Please include units with a single space between the number and the units.

QUESTION 8

When a clock signal changes from 0 to 1, this is referred to as the...

Period

Falling edge

Rising edge

Frequency

QUESTION 9

What is the frequency of a clock with a period of 500 ns?

Note: This answer will be autograded. Please include units with a single space between the number and the units.

QUESTION 10

What is the minimum number of bits required in order for a state register to represent an FSM with 6 states?

Period

Falling edge

Rising edge

Frequency

Explanation / Answer

1. number of possible states = 25 =32

2. Falling edge when clock changes from 1 to 0

4. clock period = 1/(16x106) = 62.5x10-9 s =62.5 ns

5. frequency of a clock with a period of 50 ms = 1/(50x10-3) = 20 Hertz

6.  number of possible states = 210= 1024 states

7. clock period for a clock with a frequency of 3.2 GHz = 1/(3.3x109) = 312.5x10-12 = 312.5 picoseconds

8.  When a clock signal changes from 0 to 1, this is referred to as the Rising Edge

9. frequency of a clock with a period of 500 ns = 1/(500x10-9) = 2 MHz

5.

6.

7.

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