A skydiver weighing 940 N opens his parachute at the appropriate height from the

Question

A skydiver weighing 940 N opens his parachute at the appropriate height from the ground. The air exerts a significant upward drag force, which is initially greater than the weight of the diver. This helps to slow the skydiver down. What is the diver's acceleration (both direction and magnitude) if the magnitude of the drag force is 1140 N?

magnitude     1 m/s2 direction     2---Select---upwarddownwardA skydiver weighing 940 N opens his parachute at the appropriate height from the ground. The air exerts a significant upward drag force, which is initially greater than the weight of the diver. This helps to slow the skydiver down. What is the diver's acceleration (both direction and magnitude) if the magnitude of the drag force is 1140 N? magnitude     1 m/s2 direction     2---Select---upwarddownward

Explanation / Answer

if drag force is 1140 N

then net force acting on diver is , 940-1140 N or -200N

-ve sign here means in upward direction as weight of a person is in downward direction.

for acceleration we need to know skydiver's mass

m = W/g = 940/9.81 = 95.82 kg

accelaration = net force/mass = 200/95.82 m/sec^2 = 2.087 m/sec^2 in upward direction

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