A skier slides down along a frictionless snow slope starting from rest at point

Question

A skier slides down along a frictionless snow slope starting from rest at point A with elevation hA = 84 m. Ignore air resistance. (a) Find the speed of the skier at point B with elevation hB = 21 m and point C with elevation hC = 62m. (b) Draw force diagrams of the skier at points A, B and C. (c) If the mass of the skier is m = 63 kg and the radius of curvature at point B is RB = 50 m nd the normal force exerted by the snow slope on the skier at point B. Compare this to the usual value of the apparent weight of the skier?

Explanation / Answer

a) at point B

applying law of conservation of energy

mg h = 0.5 vb2

vb 35.14m/s

at point c

mg h = 0.5 mvc2

vc 20.76 m/s

c) vb=35.14

normal force=N= mvb2/r=1555.87 N

apparent weight = mg =63*9.8=617.4

the Normal force is more than apparent weight ... it is because to provide centripetal acceleration

please rate the answer according to its quality .. i mean rate the best answer first

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