A crate with a mass of 189.5 kg is suspended from the end of a uniform boom with

Question

A crate with a mass of 189.5 kg is suspended from the end of a uniform boom with a mass of 76.1 kg. The upper end of the boom is supported by a cable attached to the wall and the lower end by a pivot (marked X) on the same wall. Calculate the tension in the cable. I need the answer and show me all the formulas to get this answer. Thanks chegg community I love you guys

A crate with a mass of 189.5 kg is suspended from the end of a uniform boom with a mass of 76.1 kg. The upper end of the boom is supported by a cable attached to the wall and the lower end by a pivot (marked X) on the same wall. Calculate the tension in the cable.

Explanation / Answer

net torque = Wb(L/2)cos(theta) + WLcos(theta) - TLsin(alpha)
I rearranged the equation
(2Tsin(alpha) - 2Wcos(theta))/cos(theta) = Wb
..please try this..hope it helps you :) :)

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