A 2.85- N metal bar, 1.75 m long and having a resistance of 10.0 (Omega) , rests

Question

A 2.85-N metal bar, 1.75m long and having a resistance of 10.0 (Omega), rests horizontally on conducting wires connecting it to the circuit shown in the figure . The bar is in a uniform, horizontal, 1.30-T magnetic field and is not attached to the wires in the circuit.

What is the magnitude of the acceleration of the bar just after the switch S is closed?

A 2.85 - N metal bar, 1.75m long and having a resistance of 10.0 (Omega), rests horizontally on conducting wires connecting it to the circuit shown in the figure . The bar is in a uniform, horizontal, 1.30 - T magnetic field and is not attached to the wires in the circuit. What is the magnitude of the acceleration of the bar just after the switch S is closed?

Explanation / Answer

F = ma

current i = V/R = 120/*35 = 3.42 Amps

so   F = ilB

F = 3.42* 1.75 * 1.3 =7.78 N

accleration a = F/m = 7.78/2.85 = 2.73 m/s^2

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