A good explanation would be great. I am having trouble with the graph analysis I

Question

A good explanation would be great. I am having trouble with the graph analysis I think.

In part (a) of the figure below, both batteries have emf = 1.25 V and the external resistance R is a variable resistor. Part (b) of the figure gives the electric potentialsV between the terminals of each battery as functions of R: Curve 1 corresponds to battery 1 and curve 2 corresponds to battery 2. The horizontal scale is set by Rs =0.32 ohm. (a/b) What is the internal resistance of battery 1 and on battery 2? good explanation would be great. I am having trouble with the graph analysis I think.

Explanation / Answer

At R = Rs/2 :

V1 + V2 = i R

(4/5)*0.5 + 0 = i * (Rs/2)

(4/5)*0.5 + 0 = i * (0.32/2)

i = 2.5 A

V1 = emf1 - i r1

(4/5)*0.5 = 1.25 - 2.5 * r1

r1 = 0.34 ohms

V2 = emf2 - i r2

0 = 1.25 - 2.5 * r2

r2 = 0.5 ohms

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