A golf club manufacturer is testing a new design for a driver that is intended t

ID: 3434742 • Letter: A

Question

A golf club manufacturer is testing a new design for a driver that is intended to produce longer drives as measured by the coefficient of the restitution for golf balls striking the club head. In a controlled experiment, the following values for coefficient of restitution were measured:

(a) Find the following:
sample mean
sample median
sample standard deviation
coefficient of variation

(b) Find a 95% confidence interval for the true mean coefficient of restitution for this type of club. State any necessary assumptions.

0.8411 0.8191 0.8182 0.8125 0.8750 0.8580 0.8532 0.8483 0.8276 0.7983

Explanation / Answer

0.8411

0.8191

0.8182

0.8125

0.8750

0.8580

0.8532

0.8483

0.8276

0.7983

(a) Find the following:
sample mean
sample median
sample standard deviation
coefficient of variation

count

mean

0.835130

sample standard deviation

0.023845

sample variance

0.000569

coefficient of variation (CV)

2.86%

median

0.834350

(b) Find a 95% confidence interval for the true mean coefficient of restitution for this type of club. State any necessary assumptions.

CI= ar x pm t *rac{s}{sqrt{n}}

t table value at 0.05 level of significance= 2.2622

CI = 0.835130 pm 2.2622 *rac{0.023845 }{sqrt{10}}

=(0.8181, 0.8522)

confidence interval 95.% lower

0.8181

confidence interval 95.% upper

0.8522

Assumptions: The data are random and independent and come from normal population. ( the population is normally distributed.)