Four voltmeters are connected to a circuit as shown in the diagram. As is usual

Question

Four voltmeters are connected to a circuit as shown in the diagram. As is usual with voltmeters, the reading on the voltmeter is positive if the negative lead (black wire, usually labeled COM) is connected to a location at lower potential, and the positive lead (red) is connected to a location at higher potential.

The circuit contains two devices whose identity is unknown, and a rod of length d = 8 cm made of a conducting material. At a particular moment, the readings observed on the voltmeters are:
Voltmeter A: 1.6 volts
Voltmeter B: 6 volts
Voltmeter C: 5.5 volts

Four voltmeters are connected to a circuit as shown in the diagram. As is usual with voltmeters, the reading on the voltmeter is positive if the negative lead (black wire, usually labeled COM) is connected to a location at lower potential, and the positive lead (red) is connected to a location at higher potential. The circuit contains two devices whose identity is unknown, and a rod of length d = 8 cm made of a conducting material. At a particular moment, the readings observed on the voltmeters are: Voltmeter A: 1.6 volts Voltmeter B: 6 volts Voltmeter C: 5.5 volts At this moment, what is the reading on Voltmeter D, both magnitude and sign? What is the magnitude of the electric field inside the bar?

Explanation / Answer

From KVL

Va+Vb+Vc+Vd=0

1.6+6+5.5+Vd=

Vd=-13.1V

E=Vd/r

r=8cm

E=-13.1/0.08

E=-1.637*10^2

/E/=163.7V/m

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