Four voltmeters are connected to a circuit as shown in the diagram. As is usual

Question

Four voltmeters are connected to a circuit as shown in the diagram. As is usual with voltmeters, the reading on the voltmeter is positive if the negative lead (black wire, usually labeled COM) is connected to a location at lower potential, and the positive lead (red) is connected to a location at higher potential.

The circuit contains two devices whose identity is unknown, and a rod of length d = 8 cm made of a conducting material. At a particular moment, the readings observed on the voltmeters are:
Voltmeter A: 1.6 volts
Voltmeter B: 6 volts
Voltmeter C: 5.5 volts

Four voltmeters are connected to a circuit as shown in the diagram. As is usual with voltmeters, the reading on the voltmeter is positive if the negative lead (black wire, usually labeled COM) is connected to a location at lower potential, and the positive lead (red) is connected to a location at higher potential. The circuit contains two devices whose identity is unknown, and a rod of length d = 8 cm made of a conducting material. At a particular moment, the readings observed on the voltmeters are: Voltmeter A: 1.6 volts Voltmeter B: 6 volts Voltmeter C: 5.5 volts At this moment, what is the reading on Voltmeter D, both magnitude and sign? What is the magnitude of the electric field inside the bar?

Explanation / Answer

sum of voltages must = 0

so
6 - 1.6 + V + 5.5 = 0

V=-9.9 V

E = V/d = 9.9/0.08= 123.8 V/m

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