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Four square sheets of thin metal are joined into a single object as shown. Each

ID: 2261623 • Letter: F

Question

Four square sheets of thin metal are joined into a single object as shown. Each of the four original squares has mass 200 g, and has sides of length 22 cm. The inset picture shows the moment of inertia of a single square sheet about its center of mass. What is the moment of inertia about an axis located at point 1?


Four square sheets of thin metal are joined into a single object as shown. Each of the four original squares has mass 200 g, and has sides of length 22 cm. The inset picture shows the moment of inertia of a single square sheet about its center of mass. What is the moment of inertia about an axis located at point 1?

Explanation / Answer

moment of inertia of a plank abot an axis passing through its center.


I = M*L^2/6


moment of inerta of block1 about the point 1 is

I1 = M*L^2/6 + M*d^2 (according to parallel axis theorem)


here d = sqrt(2)*L/2

   = M*L^2/6 + M*L^2/2

   = (4/6)*M*L^2

   = (2/3)*M*L^2

in the simillar way

for block2, I2 = (2/3)*M*L^2

for block3, I3 = (2/3)*M*L^2


for block4, I4 = M*L^2/3 + M*d^2 (according to parallel axis theorem)

here d = sqrt( L^2/4 + 9*L^2/4)

       = sqrt(10)*L/2

I4 = M*L^2/6 + M*10*L^2/4


   = (2*M*L^2 + 30*M*L^2)/12


   = (32/12)*M*L^2



I = I1+I2+I3 + I4

= 3*(2/3)*M*L^2 + (32/12)*M*L^2

= (24*M*L^2 + 32*M*L^2)/12

= (56/12)*M*L^2


I = (56/12)*0.2*0.22^2

= 0.04517 kg.m^2


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