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6. You walk 100 m to the north, and then you turn 700 to your right and then wal

ID: 2277018 • Letter: 6

Question


6. You walk 100 m to the north, and then you turn 700 to your right and then walk another 50 m. What is the magnitude of your total displacement?
13. A 1.00 kg mass, with an initial velocity of 5.00 m/s, is sliding along a horizontal surface. After 3.00 s the mass comes to a rest. What is the coefficient of kinetic friction? 14. An ideal frictionless Atwood Machine has two masses attached to it, m1= 2.00 kg, and m2=4.00 kg. What is the tension in the string?
15. An ideal frictionless Atwood Machine has two masses attached to it, m1= 2.00 kg, and m2=4.00 kg. What is magnitude of the acceleration of the masses?
6. You walk 100 m to the north, and then you turn 700 to your right and then walk another 50 m. What is the magnitude of your total displacement?
13. A 1.00 kg mass, with an initial velocity of 5.00 m/s, is sliding along a horizontal surface. After 3.00 s the mass comes to a rest. What is the coefficient of kinetic friction? 14. An ideal frictionless Atwood Machine has two masses attached to it, m1= 2.00 kg, and m2=4.00 kg. What is the tension in the string?
15. An ideal frictionless Atwood Machine has two masses attached to it, m1= 2.00 kg, and m2=4.00 kg. What is magnitude of the acceleration of the masses? 13. A 1.00 kg mass, with an initial velocity of 5.00 m/s, is sliding along a horizontal surface. After 3.00 s the mass comes to a rest. What is the coefficient of kinetic friction? 14. An ideal frictionless Atwood Machine has two masses attached to it, m1= 2.00 kg, and m2=4.00 kg. What is the tension in the string?
15. An ideal frictionless Atwood Machine has two masses attached to it, m1= 2.00 kg, and m2=4.00 kg. What is magnitude of the acceleration of the masses?

Explanation / Answer

a) Total displacement = 100 j + 50* sin 70 i + 50* cos 70 j = 46.9846 i + 117.101 j

magnitude = sqrt (46.98^2 + 117.1^2 ) = 126.17


b) a = v/t = 5/3 m/s^2

u*g = 5/3

u = 5/3g = 5/(3*9.8) = 0.17


c) 4*g - T = 4*a

T - 2*g = 2*a

add these two

2*g = 6*a

a = g/3


T = 2*(g+a) = 2*(g+g/3) = 8*g/3 = 26.133 N


d) a = g/3 = 3.2667 m/s^2