Hello, doing a Physics experiment, Pretty basic for most, but a little tough for

Question

Hello, doing a Physics experiment, Pretty basic for most, but a little tough for me. I don't want the answer, I need to figure out the formuls it is asking for.

Data:

D = 7.62cm

r= 3.81cm

increase in water level h=1.905cm

Volume of water displaced = 86.83cm3

Find the mass of the Ice

"To do this, note that you just found the volume of the water displaced. The mass of this volume of water is equal to the mass of the ice. This mass can be found by:

Where m is mass,p is the density of water (1 gm/cm^3) , and V is volume of water displaced."

This is where I'm stuck, what is the formula?

I got it...... the answer is D=M/V   or m=d*v   or 1gm/cm3* 86.83cm3 so the answer is 86.83cm3

Explanation / Answer

Mass of the water displaced = mass of ice

mass = Density * volume = p*V

p*V = mass of ice

mss of ice = 86.83 *1 = 86.83 g

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