Two weights are hanging as shown in the figure ( Figure 1 ) . Two weights are ha
ID: 2276597 • Letter: T
Question
Two weights are hanging as shown in the figure(Figure 1) . Two weights are hanging as shown in the figure(Figure 1) . Two weights are hanging as shown in the figure(Figure 1) . Two weights are hanging as shown in the figure(Figure 1) . Part A Find the tension in cable A if w1 = 88.0N and w2 = 160N . TA = N Part B Find the tension in cables B and C. TB=TC= = N Provide FeedbackContinue Part A Find the tension in cable A if w1 = 88.0N and w2 = 160N . TA = N Part B Find the tension in cables B and C. TB=TC= = N Part A Find the tension in cable A if w1 = 88.0N and w2 = 160N . TA = N Part B Find the tension in cables B and C. TB=TC= = N Part A Find the tension in cable A if w1 = 88.0N and w2 = 160N . TA = N Part B Find the tension in cables B and C. TB=TC= = N Part A Find the tension in cable A if w1 = 88.0N and w2 = 160N . TA = N Part A Find the tension in cable A if w1 = 88.0N and w2 = 160N . TA = N TA = N TA = N Part B Find the tension in cables B and C. TB=TC= = N Part B Find the tension in cables B and C. TB=TC= = N TB=TC= = N TB=TC= = N Provide FeedbackContinue Figure 1 of 1 Two weights are hanging as shown in the figure(Figure 1) . Part A Find the tension in cable A if w1 = 88.0N and w2 = 160N . TA = N Part B Find the tension in cables B and C. TB=TC= = N Provide FeedbackContinue Figure 1 of 1 Find the tension in cable A if w1 = 88.0N and w2 = 160N . Find the tension in cables B and C.Explanation / Answer
tension in cable A =w2=160N
considering equilibrium on body w1 we get
w1+w2=2*Tb*cos(30)
so Tb=143.182N
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