Two very small spheres have charges of 3.0 mu C and -6.0 mu C are placed 2.0 cm

Question

Two very small spheres have charges of 3.0 mu C and -6.0 mu C are placed 2.0 cm away from each other. The magnitude of the electric force on each sphere is? 0.081 N 0.040 N 8.01 N 4.0 times 10^2 N Two identical objects, one neutral and the other with a charge of +4.0 mu C, are brought into contact and then separated to distance of 0.25 m. Calculate the magnitude of the electrostatic force between the two charged objects. 0.14N 0.58N 1.4 times 10^10 N 5.4 times 10611 N A uniform electric field of 440N/C exists between two large metal plates that are 40 cm apart. The potential difference between the plates is 1.8 times 10^4 V 1.1 times 10^3 V 1.8 times 10^2 V 1.1 times 10^2 V A 8.20 times 10^25 kg oil drop is moving upwards at a constant speed of 1.60 m/s between two horizontal parallel plates. If the electric field strength between the plates is 2000 V/m, determine the magnitude of the drop's charge 2.51 times 10^-2 C 251 C 1.6 times 10^-19 C 4.0 times 10^-19 C

Explanation / Answer

Part A

magnitude of force between the particles

|F|= k |q1|* |q2| / r^2

F = 9 x 10^9 * 3 x 10^-6 * 6 x 10^-6 / (0.02)^2

F = 405 N = 4 x 10^2 N

Part B

after the contact between them, both the spheres carries same amount of charge that is equal to +2.0 x 10^-6 C

Force.....

|F|= k |q1|* |q2| / r^2

F = 9 x 10^9 * 2 x 10^-6 * 2 x 10^-6 / (0.25)^2

F= 0.576 N

Part C

potential difference is given by ..........V = -Ed

we get ..........V = 440 * 0.4 = 176 V = 1.8 x 10^2 V

Part D

since the drop of oil us moving with the constant velocity hterefore the net force ont he drop is zero

one force is mg and other in opposite direction that is qE

we get ...........qE = mg

q = mg / E = 8.2 x 10^-15 * 10 / 2000 = 4.1 x 10^-17 C

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