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Two very large parallel sheets are 5.00 cm apart. Sheet A carries a uniform surf

ID: 1479712 • Letter: T

Question

Two very large parallel sheets are 5.00 cm apart. Sheet A carries a uniform surface charge density of -8.80 C/m2 , and sheet B, which is to the right of A, carries a uniform charge of -11.9 C/m2 . Assume the sheets are large enough to be treated as infinite.

Part a.

Find the magnitude of the net electric field these sheets produce at a point 4.00 cm to the right of sheet A.

Part B

Find the direction of the net electric field these sheets produce at a point 4.00 cm to the right of sheet A.

Part C

Find the magnitude of the net electric field these sheets produce at a point 4.00 cm to the left of sheet A.

Part D

Find the direction of the net electric field these sheets produce at a point 4.00 cm to the left of sheet A.

Part E

Find the magnitude of the net electric field these sheets produce at a point 4.00 cm to the right of sheet B.

Part F

Find the direction of the net electric field these sheets produce at a point 4.00 cm to the right of sheet B.

Explanation / Answer

electric field due to infinite sheet of charge = linear charge density / e0

the magnitude of the net electric field these sheets produce at a point 4.00 cm to the right of sheet A = electric field due to A - electric field due to B

because direction of electric field are opposite

the magnitude of the net electric field these sheets produce at a point 4.00 cm to the right of sheet A = -8.8 * 10^-6 / e0 - (-11.9 * 10^-6 / e0)

the magnitude of the net electric field these sheets produce at a point 4.00 cm to the right of sheet A = 3.1 * 10^-6 / (8.85 * 10^-12)

the magnitude of the net electric field these sheets produce at a point 4.00 cm to the right of sheet A = 350282.485 N/C

direction will be toward sheet B

magnitude of the net electric field these sheets produce at a point 4.00 cm to the left of sheet A = electric field due to A + electric field due to B

because direction of electric field are same

the magnitude of the net electric field these sheets produce at a point 4.00 cm to the left of sheet A = -8.8 * 10^-6 / e0 + (-11.9 * 10^-6 / e0)

the magnitude of the net electric field these sheets produce at a point 4.00 cm to the left of sheet A = -20.7 * 10^-6 / (8.85 * 10^-12)

the magnitude of the net electric field these sheets produce at a point 4.00 cm to the left of sheet A = -2338983.05 N/C

direction will be toward sheet A