1. An ideal gas is held in a rigid container whose volume is 0.25 m An ideal gas
ID: 2273553 • Letter: 1
Question
1. An ideal gas is held in a rigid container whose volume is 0.25 m
An ideal gas is held in a rigid container whose volume is 0.25 m3. It is heated from 100 degree C, where it is at a pressure of 2 x 105 Pa, to a final temperature of 250 degree C. What is the change in pressure of the gas? A piece of solid lead weighing 6.5 kg at 327 degree C (its melting point) receives 150,000 joules of heat. In what state is the lead after this occurs? The latent heat of fusion for lead is 23,200 J/kg. Which of the following arrangements of three masses (hanging off the horizontal rod) would result in a balanced mobile?Explanation / Answer
1) for ideal gas P is directly proportional to temperature at constant volume
hence P1/T1 = P2/T2 => P2 = P1*T2/T1 = 2*105*523/373 = 294.45 Pa (temperature in kelvin)
2) heat required to melt 6.5 kg of lead = latent heat*mass = 23200*6.5 = 150800 J
heat supplied = 150000 J
mass of lead which willl melt = 150000/23200 = 6.4655 Kg
mass of lead which will remain solid = 0.0345 Kg
3)there is no arrangement shown below part 3
CASE 1 cosidering mass 1 at left extreme and mass 3 at right extreme and mass 2 x metre left of centre
balancing torque
2*1 + 1*x = 4*1
=> x = 2 m not possible
CASE 2 considering mass 1 at left extreme amd mass 2 at right extreme and mass 3 x metre right of centre
balancing torque
2*1 = 1*1 + 4*x
=> x = .25 m
4) answer is I. Speed = 0m/s
@ extreme position in a spring mass system acceleration and diplacement is maximum
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.