Two point charges, 3.0 C and -2.0 C, are placed 6.0 cm apart on the x axis, such

Question

Two point charges, 3.0 C and -2.0 C, are placed 6.0 cm apart on the x axis, such that the -2.0 C charge is at x = 0 and the 3.0 C charge is at x = 6.0 cm.

x < 0 cm
0 < x < 6.0 cm cm
6.0 cm < x cm
Two point charges, 3.0 mu C and -2.0 mu C, are placed 6.0 cm apart on the x axis, such that the -2.0 mu C charge is at x = 0 and the 3.0 mu C charge is at x = 6.0 cm. At what point(s) along the x axis is the electric field zero? (If there is no point where E = 0 in a region, enter "0" in that box.) At what point(s) along the x axis is the potential zero? Let V = 0 at r = ?. (If there is no point where V = 0 in a region, enter "0" in that box.)

Explanation / Answer

one is attractive and the another one is repulsive force due to opposite charge.

as positive charge is stronger then possibly the point will be further from that charge.

so lets assume the point is -r.

so equating the field we would get

2/r^2 = 3/(6+r)^2

solving and taking the positive value of r we get

r= 1.416 cm. so x= -1.416 cm

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