Two point charges are separated by 6cm. The attracticeforce between them is 20N.

Question

Two point charges are separated by 6cm. The attracticeforce between them is 20N. Show that when separated by 12cm,the force between them is 5N. Why can you solve this problemwithout knowing the magnitides of the charges? _______________________ I believe it has to do with Coulomb's Law that 2 objects thatare much smaller than the distance between them, the force betweenthem varies directly as the product of their charges and inverselyas the square of the separation distance. The formula I believe isF=k(q1q2/d2) Where d is the distance between the charged particles q1 represents the quanitiy of charge of oneparticle q2 represents the quantity of charge of the secondparticle k is the proportionality constant(9*109N*m2/c2) Force is 20N when the points are separated by 6cm then, Force is 5N when the points are separated by 12cm. I'm not sure from here. Is this the right formula? or isthere a simpler way to show the relationship between the distanceand the force? Two point charges are separated by 6cm. The attracticeforce between them is 20N. Show that when separated by 12cm,the force between them is 5N. Why can you solve this problemwithout knowing the magnitides of the charges? _______________________ I believe it has to do with Coulomb's Law that 2 objects thatare much smaller than the distance between them, the force betweenthem varies directly as the product of their charges and inverselyas the square of the separation distance. The formula I believe isF=k(q1q2/d2) Where d is the distance between the charged particles q1 represents the quanitiy of charge of oneparticle q2 represents the quantity of charge of the secondparticle k is the proportionality constant(9*109N*m2/c2) Force is 20N when the points are separated by 6cm then, Force is 5N when the points are separated by 12cm. I'm not sure from here. Is this the right formula? or isthere a simpler way to show the relationship between the distanceand the force? Force is 20N when the points are separated by 6cm then, Force is 5N when the points are separated by 12cm. I'm not sure from here. Is this the right formula? or isthere a simpler way to show the relationship between the distanceand the force?

Explanation / Answer

yes your gauss is correct coulpmb's law will be applicable as this is point charge you can write the formulaas F= k Q2/r2 according to given data 20 N =k Q2/36 puttingr=6 so Q2= 20N*36/k so the force between them when they separated 12 cm is k *20*36/k*144 =5N according to given data 20 N =k Q2/36 puttingr=6 so Q2= 20N*36/k so the force between them when they separated 12 cm is k *20*36/k*144 =5N

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