Two point charges are fixed on the y axis: a negativepoint charge q 1 = -28µC at

Question

Two point charges are fixed on the y axis: a negativepoint charge q1 = -28µC at y1 = +0.25m and a positive point charge q2 aty2 = +0.32 m. A thirdpoint charge q = +8.5 µC isfixed at the origin. The net electrostatic force exerted on thecharge q by the other two charges has a magnitude of28 N and points in the +ydirection. Determine the magnitude ofq2.
Answer should be in coulombs Thanks in Advance Two point charges are fixed on the y axis: a negativepoint charge q1 = -28µC at y1 = +0.25m and a positive point charge q2 aty2 = +0.32 m. A thirdpoint charge q = +8.5 µC isfixed at the origin. The net electrostatic force exerted on thecharge q by the other two charges has a magnitude of28 N and points in the +ydirection. Determine the magnitude ofq2.
Answer should be in coulombs Thanks in Advance

Explanation / Answer

First we find the force on q by q1 using Coulomb's Law F = k*q*q1/r^2 = 9.0x10^9N-m^2/C^2*8.5x10^-6C*28x10^-6C/(0.25 m)^2= 34.3N and it points up Now since the resulting force is 28N up the force on q by q2 mustpoint down and have a magnitude of 34.3 - 28. = 6.3N. Now for the magnitude F = 6.3 = k*q*q2/r^2 so q2 = 6.3N*r^2/(k*q) =6.3*(0.32)^2/(9x10^9*8.5x10^-6) = 8.4x10^-6C = 8.4 µC

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