please answer it indetail. the answer is wrong. (25 points) This problem is rela

Question

please answer it indetail. the answer is wrong.

(25 points) This problem is related to 1.15 in the text. A sequence of analog signals (indexed by k ) is defined by Zk(t) cos(2nit + ). The sampled signals are created by sampling the analog signals every T seconds. The sampling frequency is F, 1/T = 15Hz, the phase is 0 0 and the sampled signals are defined by Zk(n) = cos(2 n + ) Fs The frequencies of the analog signals are 2,5.5,9.5,13) Give the frequency that each of the sampled analog signal will appear to be. analog frequency = 2 HZ is seen as 215 analog frequency 5.5 HZ is seen as 1.13 analog frequency 9.5 HZ is seen as 9.5/15 analog frequency = 13 Hz is seen as 1315 Hz Hz Hz Hz

Explanation / Answer

for 2 Hz it will be = fs + fk or fs - fk Because when we do sampling the frequency translation is occur one freqency is up conversion and another is down converter.

= 15+2=17 Hz or 15-2 = 13 Hz

for 5.5 Hz = 15+5.5 = 20.5 Or =15-5.5 = 9.5 Hz

for 9.5 Hz = 15+9.5 = 24.5 Or =15-9.5 = 4.5 Hz

for 13 Hz = 15+13 = 28 Or =15-13 = 2 Hz

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