please answer correctly and quickly 8. Balance cach of the following equations:
ID: 1027022 • Letter: P
Question
please answer correctly and quickly
8. Balance cach of the following equations: (a) H:S0 aLiOH(aq)LiSO4(aq) +HOU) (b) CsHs(g) 02(g)C02(g)+ H:0(g) (c) MgCOs(s)HNO,(a) Mg(NOs(a)Cog) H00) 9. Use the equation below to calculate the mass of ZnCl; obtained by reacting 12.0 of zine metal with dilute hydrochloric acid: 10-An organic compound was found to contain 40 00% C: 6.71% H, and 53.28% O. The molecular mass was 90.08 amu. What is the molecular formula of the compound? Bonus Q. Up to 10 marks will be added to your marks if correctly answer Q. 11: 11.Complete combustion of a hydrocarbon gave 5.86 mg of CO; and 1.37 mg of water. What is the empirical formula of the compound?Explanation / Answer
8. H2So4(aq) + 2LiOH(aq) ----------> Li2So4(aq) + 2H2O(l)
b C3H8(g) + 5O2 -----------> 3Co2(g) + 4H2O(g)
c. MgCo3(s) + 2HNO3(aq) ----------> Mg(NO3)2(aq) + Co2(g) + H2O(l)
9.
Zn(s) + 2HCl(aq) ----------> ZnCl2(aq) + H2(g)
1moles of Zn react with HCl to gives 1 moles of ZnCl2
65.4g of Zn react with HCl to gives 136.4g of ZnCl2
12g of Zn react with HCl to gives = 136.4*12/65.4 = 25g of ZnCl2
10.
Elemetn % A.Wt relative numer simple ratio
C 40 12 40/12 = 3.33 3.33/3.33 = 1
H 6.71 1 6.71/1 = 6.71 6.71/3.33 =2
O 53.28 16 53.28/16 = 3.33 3.33/3.33 = 1
The empirical formula = CH2O
molecular formula = (empirical formula)n
n = M.Wt/E.F.Wt
= 90.08/30 = 3
The molecular formula = (CH2O)2 = C2H4O2
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