A block of mass m 1 = 1 kg rests on a table with which it has a coefficient of f

Question

                    A block of mass m1= 1 kg rests on a table with which it has a coefficient of friction

A block of mass m1 = 1 kg rests on a table with which it has a coefficient of friction mu = 0.55. A string attached to the block passes over a pulley to a block of mass m3 = 3 kg. The pulley is a uniform disk of mass m2 = 0.5 kg and radius 15 cm. As the mass m3 falls, the string does not slip on the pulley. With what acceleration does the mass m3 fall? a = What is the tension in the horizontal string, T1? T1 = What is the tension in the vertical string, T3? T3 =

Explanation / Answer

Let m3 fall with acceleration a
Then a = linear acceleration of a point on the rim of the pulley
Angular acceleration of the pulley alpha = a/R ----------------------(1)
(where R = radius of pulley)

For m3
m3 * g - T3 = m3 * a
Or T3 = m3 * g - m3 * a---------------------------(2)

m1 moves horizontally with acceleration a.
Therefore T1 -

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