Question Part Points Submissions Used Item 2 A rifle bullet with mass 8.00 g str
ID: 2264225 • Letter: Q
Question
Explanation / Answer
B = u0/4 pi q v x rhat/r^2
so for postive charge out of the page
for electron also out of page
so B = (u0/ 4pi) v/r^2 ( 2e + e)*sin(140)
B = 10^(-7)*2.6E5/(1.8E-9^2) *3*1.6E-19*sin(140)=0.0025 T out of page
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