1_Two point charges are separated by 1.5 cm. Charge A has a charge of +2.0 uC an
ID: 2256106 • Letter: 1
Question
1_Two point charges are separated by 1.5 cm. Charge A has a charge of +2.0 uC and Charge B has a charge of +4.0 uC.
1.a_What is the value of the electric force of Charge B acting on A?
1.b_What is the direction?
2__Find the electrostatic potential difference due to point p, located at the center of the square in the diagram. Leave the answer as Q and d.
3) Four charges are placed at four corners of a square (in the previous fig), where d = 0.50 m and Q = 2.9 uC. Find the magnitude and direction of the net electric force on the Q located in the top left side. Notice the charge in the top right side is -2Q (negative).
Two point charges are separated by 1.5 cm. Charge A has a charge of +2.0 uC and Charge B has a charge of +4.0 uC. What is the value of the electric force of Charge B acting on A? What is the direction? Find the electrostatic potential difference due to point p, located at the center of the square in the diagram. Leave the answer as Q and d. Four charges are placed at four corners of a square (in the previous fig), where d = 0.50 m and Q = 2.9 uC. Find the magnitude and direction of the net electric force on the Q located in the top left side. Notice the charge in the top right side is -2Q (negative).Explanation / Answer
1) F = K*Qa*Qb/r^2 = (9*10^9*2*10^-6*4*10^-6)/((1.5*10^-2)^2)= 320 N
2) dV = (K/d?2)*[Q-2Q+Q+Q] = KQ/d?2
3) Fx = -K*2Q*Q/4d^2 - K*Q*2Q*cos45/8d^2 = -0.2049 N
Fy =- K*Q*2Q/4d^2 - K*Q*2Q*cos45/8d^2 = -0.2049 N
F = 0.2897 N
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