Figure 18-46 shows a hydraulic lift operated by pumping fluid into the hydraulic

Question

Figure 18-46 shows a hydraulic lift operated by pumping fluid into the hydraulic system. The large cylinder is 20 cm in diameter, while the small tube leaving the pump is 1.7 cm in diameter. A total load of 2600 kg is raised 2.1 m at a constant rate. Neglect pressure variations with height, and neglect also the weight of the fluid raised.

Figure 18-46 shows a hydraulic lift operated by pumping fluid into the hydraulic system. The large cylinder is 20 cm in diameter, while the small tube leaving the pump is 1.7 cm in diameter. A total load of 2600 kg is raised 2.1 m at a constant rate. Neglect pressure variations with height, and neglect also the weight of the fluid raised. What volume of fluid passes through the pump? m3 What is the pressure at the pump outlet? atm How much work does the pump do? kJ If the lifting takes 40 s, what is the pump power? kW

Explanation / Answer

Volume passed through the pump would be = area of the large cylinder * increase in height of the car

= 3.14 * (0.1^2 ) * 2.1 m^3 = 0.066 m^3

Let , pressure after pump = P1

so, P1 * (area of thin tube) = mass * g

P1 * (3.14 * ((1.7/2)^2)) = 2600 * 9.8

So, P1 = 11231.34 Pa

Work done by pump = mass * g * height raised = 2600 * 9.8 * 2.1 Joules = 53508 Joules

Power = work done by time = 53508 / 40 Watt = 1337.7 Watt

  

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