Figure 12-11 shows a thin, uniform rod of length 0.600 m and mass M that is rota

Question

Figure 12-11 shows a thin, uniform rod of length 0.600 m and mass M that is rotating horizontally counterclockwise about an axis through its center, at an angular velocity of 76.0 rad/s. A particle of mass M/3.00 and speed 41.0 m/s hits and then sticks to the rod. The particle's path is perpendicular to the rod at the instant of the hit, at a distance d from the rod's center.

(a) At what value of d are the rod and particle stationary after the hit?
m(b) In which direction do the rod and particle rotate if d has a lesser value?

counterclockwiseclockwise

Explanation / Answer

a)
Let, M is the mass of rod.

masss of particle, m = M/3

length of the rod, L = 0.6 m

Apply conservation of anglau momentum

Initial angular momentum = final agnular momenum

I*w - m*v*d = 0

d = I*w/(m*v)

= (M*L^2/12)*w/(M*v/3)

= 3*L^2*w/(12*v)

= 3*0.6^2*76/(12*41)

= 0.167 m <<<<<-------Answer

b) counterclockwise

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.