A hotair balloonist, rising vertically with a constant speed of 5.00m/s m/s, rel

Question

A hotair balloonist, rising vertically with a constant speed of 5.00m/s m/s, releases a sandbag at the instant the balloon is 40.0m above the ground. (See the figure (Figure 1)After it is released, the sandbag encounters no appreciable air drag. Compute the position (height above the ground) of the sandbag at 0.264ss Compute the position of the sandbag 1.06s s after its release. )Compute the x component of the velocity of the sandbag at 0.264s s s after its release. Compute the x component of the velocity of the sandbag at 1.06s s How many seconds after its release will the bag strike the ground? What is the greatest height above the ground that the sandbag reaches?

Explanation / Answer

a) h = 40.0 + 5.00*t -

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