A 42.0 kg child takes a ride on a Ferris wheel that rotates four times each minu

Question

A 42.0 kg child takes a ride on a Ferris wheel that rotates four times each minute and has a diameter of 24.0 m.

a) The centripetal acceleration of the child is 2.11 m/s2

b) The force does the seat exert on the child at the lowest point of the ride?

is 500.2 N at 0 degrees.
(c) The force does the seat exert on the child at the highest point of the ride is 322.98 degrees.
Magnitude


(d) The force does the seat exert on the child when the child is halfway between the top and bottom is 421.0 N.... What is the direction is degrees upward?

(I tried doing tan-1(411.6/88.62) but it is not the correct answer)

Explanation / Answer

force at the lowest point is

Fb = m x (a + g)

where m = 42.0 kg,a = 2.11 m/s^2 and g = 9.8 m/s^2

force at the highest point is

Ft = m x (g - a)

the force when the child is halfway is

F = Fb + Ft/2

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