1) 2) 3) 4) 5) 6) A monochromatic laser beam of intensity Io = 692 W/m2 is polar
ID: 2251028 • Letter: 1
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A monochromatic laser beam of intensity Io = 692 W/m2 is polarized in the y-direction and propagates in the positive z-direction. This beam is incident upon a quarter-wave plate whose fast axis makes an angle of 45 degrees with the x-axis as shown. Following the quarter-wave plate are two polarizers; the transmission axis of the first polarizer is aligned with the x-axis, while the transmission axis of the second polarizer makes an angle of ?1 = 79 degrees with the positive x axis. What is Imid, the intensity of the beam immediately following the polarizer whose transmission axis is aligned with the x-axis? What is Ifinal, the intensity of the beam immediately following the last polarizer? What is the ratio of Ey,final, the maximum value of the y-component of the electric field immediately following the last polarizer, to Eo, the amplitude of the electric field oscillations in the incident polarized beam? The positions of the quarter-waveplate and the last polarizer are now interchanged. What is Ifinal,new, the intensity of the beam after passing through the new arrangement of the two polarizers and the quarter-wave plate? What is the polarization of the beam immediately following the quarter-wave plate? Right Circularly Polarized Left Circularly Polarized Linearly polarized at 45 degrees to the positive x-axis. Linearly polarized at 135 degrees to the positive x-axis. Suppose you are free to rotate ?1, the transmission axis of the initial polarizer. How many values of ?1, 0 ? ?1Explanation / Answer
1) Imid = I0 cos^2(45)
= 692*cos^2(45)
= 346 W/m^2
2) Since we already know the first intensity drop we can use the Law of Malus to find the second using a difference angle of 79 degrees.
Ifinal = Imid cos^2(theta1)
= 346*cos^2(79)
= 12.59 W/m^2
3) Converting from intensity to electric field, since we
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