Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

A steel ball bearing is 7 cm in diameter at 17?C. A bronze plate has a hole that

ID: 2244647 • Letter: A

Question

A steel ball bearing is 7 cm in diameter at 17?C. A bronze plate has a hole that is 6.994 cm in diameter at 17?C.

What common temperature must they have in order for the ball to just squeeze through the hole?

Answer in units of ?C

A steel ball bearing is 7 cm in diameter at 17?C. A bronze plate has a hole that is 6.994 cm in diameter at 17?C. What common temperature must they have in order for the ball to just squeeze through the hole? alpha (steel) = 1.1x10^-5 per degree Celsius alpha (bronze) = 1.9x10^-5 per degree Celsius I got 107.3614143 C and it says the answer is wrong. I used the equation: Lest = Libra [7.000 cm] [ 1 + ( 1.1 x 10 - 5 (Co) - 1) delta T ] = [6.994 cm] [ 1 + ( 1.9 x 10 - 5 (Co) - 1) delta T ]

Explanation / Answer

107.3614143 C is change in temperatue.

final temperature = 107.3614143 C + 17 C = 124.36*C

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote