a ray in glass arrives at the glass-water interface at an angle of 48 degrees wi
ID: 2244520 • Letter: A
Question
a ray in glass arrives at the glass-water interface at an angle of 48 degrees with the normal. the refracted ray, in water, makes a 68 degree angle with the normal. the index of refraction of water is 1.33. in the figure, the angle of incidence of a second ray in the glass is 39 degrees. what is the angle of refraction in the water of the second ray? ****please show all work/steps****
a ray in glass arrives at the glass-water interface at an angle of 48 degrees with the normal. the refracted ray, in water, makes a 68 degree angle with the normal. the index of refraction of water is 1.33. in the figure, the angle of incidence of a second ray in the glass is 39 degrees. what is the angle of refraction in the water of the second ray?Explanation / Answer
from snells law,
sin x(glass)/sin x(water) = n(water)/n(glass)
From first data,
n(water)/n(glass)= sin 48/sin 68
Substituting the values of refractive index in second data,
sin 39/sin x(water) = n(water)/n(glass)
sin 39/sin x(water) = sin 48/sin 68
sin x(water)=sin 39*sin 68/sin 48=51.73 degrees
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