Two speakers face each other and radiate coherently and in phase. The speakers a

Q: Two speakers face each other and radiate coherently and in phase. The speakers a

d = 5.5 m a) v = lamda*f lamda = v/f = 340/272 = 1.25 Hz b)at the center constructive interferece takes place. so we here a loud sound. c) we need to move lamda/2 distance x = lamda/2 = 1.25/2 = 0.625 m d) n = d/lamda - 5.5/1.25 = 4.4 so, at 4 times constructive interference takes place. so, at 4 places we can here loud sound.

ID: 2242723 • Letter: T

Question

Two speakers face each other and radiate coherently and in phase. The speakers are separated by a distance of 5.5m and emit a sound with a frequency of 272 Hz. Use 340m/s for the speed of sound in air.

a.) What is the wavelength of the sound?

b.) You happen to be standing exactly half-way between the speakers. Will you have a loud maximum or a soft minumum?

c.) How far do you need to travel to a speaker in order to have the sounds change (i.e. loud to soft or soft to loud)?

d.) How many loud maximum intensity positions are there between the speakers? (Hint - find distance between one maximum and the next)

Explanation / Answer

d = 5.5 m

a) v = lamda*f

lamda = v/f = 340/272 = 1.25 Hz

b)at the center constructive interferece takes place. so we here a loud sound.

c) we need to move lamda/2 distance

x = lamda/2 = 1.25/2 = 0.625 m

d)

n = d/lamda - 5.5/1.25 = 4.4

so, at 4 times constructive interference takes place.

so, at 4 places we can here loud sound.

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Two speakers face each other and radiate coherently and in phase. The speakers a

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