Two speakers emit sound waves with frequency of 418 Hz. They are driven by the s

Question

Two speakers emit sound waves with frequency of 418 Hz. They are driven by the same oscillator so that they are in phase with each other. We place the speakers so that they are a few meters apart and facing each other. Along the line joining the two speakers, the sound waves from the two speakers are traveling in opposite directions. This creates a standing waves between the two speakers. How far apart are the antinodes in that standing wave? Neglect the effect of reflection of waves from the speakers. The speed of sound is 343 m/s

Explanation / Answer

Here is what I solved before, please modify the figures as per your question. Please let me know if you have further questions. If this helps then kindly rate 5-stars.

Two speakers emit sound waves with frequency 4.71 kHz. They are driven by the same oscillator so that they are in phase with each other. I place the speakers side-by-side, and I stand across the room from them. If someone moves ones of the speakers toward me, I hear the total intensity drop and then rise again. How far (cm) did he move the speaker to the point where I heard a minimum intensity due to destructive interference of the sound waves from the two speakers? The speed of sound is 343 m/s.

sol:

the difference in phase when destructive interference occurs is pi.
so difference in distance.
lamda/2.
lamda=v/f=0.073
so s=lamda/2=0.036=3.6(cm)

pls rate first. thanks alot

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