Two masses, M 1 = 2.0 kg and M 2 = 0.29 kg, are at rest on an air-track with a c

Question

Two masses, M1= 2.0 kg and M2= 0.29 kg, are at rest on an air-track with a compressed spring between them. The spring is released; the force on M1as a function of time is shown. Find the speed of M2when t= 20.0 milliseconds.

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Two masses, M1 = 2.0 kg and M2 = 0.29 kg, are at rest on an air-track with a compressed spring between them. The spring is released; the force on M1 as a function of time is shown. Find the speed of M2when t= 20.0 milliseconds.

Explanation / Answer

The force acting on the two masses will be same.

Therefore the force acting on M2 is 48 N from graph.
The acceleration on the body at given t is 48/0.29 kg = 165.5 m/sec^2
Velocity is 165.5*20*10-^-3 = 3.31 m /sec

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